Termination w.r.t. Q of the following Term Rewriting System could be proven:
Q restricted rewrite system:
The TRS R consists of the following rules:
g(a) → g(b)
b → f(a, a)
f(a, a) → g(d)
Q is empty.
↳ QTRS
↳ Overlay + Local Confluence
Q restricted rewrite system:
The TRS R consists of the following rules:
g(a) → g(b)
b → f(a, a)
f(a, a) → g(d)
Q is empty.
The TRS is overlay and locally confluent. By [19] we can switch to innermost.
↳ QTRS
↳ Overlay + Local Confluence
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
g(a) → g(b)
b → f(a, a)
f(a, a) → g(d)
The set Q consists of the following terms:
g(a)
b
f(a, a)
Using Dependency Pairs [1,15] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:
F(a, a) → G(d)
B → F(a, a)
G(a) → G(b)
G(a) → B
The TRS R consists of the following rules:
g(a) → g(b)
b → f(a, a)
f(a, a) → g(d)
The set Q consists of the following terms:
g(a)
b
f(a, a)
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ Overlay + Local Confluence
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ DependencyGraphProof
Q DP problem:
The TRS P consists of the following rules:
F(a, a) → G(d)
B → F(a, a)
G(a) → G(b)
G(a) → B
The TRS R consists of the following rules:
g(a) → g(b)
b → f(a, a)
f(a, a) → g(d)
The set Q consists of the following terms:
g(a)
b
f(a, a)
We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph [15,17,22] contains 0 SCCs with 4 less nodes.